Matematika Sekolah Menengah Atas assalamualikum tolong di jawab yaaa semoga yang jawab sehat selalu​

assalamualikum tolong di jawab yaaa semoga yang jawab sehat selalu​

1

[tex]m {}^{5} \times m {}^{0} \times m = m {}^{5 + 0 + 1} = m {}^{6} \\ [/tex]

2

[tex]3 {}^{2} + 3 {}^{3} + 3 {}^{4} = 9 + 27 + 81 = 117 \\ [/tex]

3

[tex]9 {}^{2} \times 3 {}^{4} \div 27 = 3 {}^{4} \times 3 {}^{4} \div 3 {}^{3} = 3 {}^{4 + 4 - 3} = 3 {}^{5} \\ [/tex]

4

[tex](3a {}^{2} ) {}^{4} = 81a {}^{8} \\ [/tex]

5

[tex](27 {}^{ \frac{1}{3} } ) {}^{7} = ((3 {}^{3} ) {}^{ \frac{1}{3} } ) {}^{7} = 3 {}^{3 \times \frac{1}{3} \times 7} = 3 {}^{7} \\ [/tex]

6

[tex] \frac{a {}^{5} b {}^{2} c {}^{4} }{a {}^{ - 2} b {}^{ - 3} c {}^{ - 4} } = a {}^{7} b {}^{5} c {}^{8} \\ [/tex]

7

[tex]10 {}^{ - 5} = 0.00001 \\ [/tex]

8

[tex]3 {}^{ - 2} + 3 {}^{ - 3} = \frac{1}{3 {}^{2} } + \frac{1}{3 {}^{3} } = \frac{1}{9} + \frac{1}{27} = \frac{3 + 1}{27} = \frac{4}{27} \\ [/tex]

9

[tex] \frac{1}{2 {}^{5} } \times \frac{1}{2 {}^{ - 6} } = \frac{2 {}^{6} }{2 {}^{5} } = 2 \\ [/tex]

10

[tex]5.2 \times 10 {}^{ - 7} \\ [/tex]

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